CL SecurehttpsiiseSsion.nastergplyslsbye Ch 10 HW Exercise 10.13 bmit Constants

Question

CL SecurehttpsiiseSsion.nastergplyslsbye Ch 10 HW Exercise 10.13 bmit Constants A textbook of mass 1.92 kg rests on a frictionless horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.170 m, to a hanging book with mass 2.93 kg. The system is released from rest, and the books are observed to move a distance 1.26 m over a time interval of O.790 s Correct Part C What is the moment of inertia of the pulley about its rotation axis? Take the free fall acceleration to be g-9.80 m/s 065 kg-m2 Submit X Incorrect: Try Again; 5 attempts remaining Provide Feedback 460.jp9 37

Explanation / Answer

The two forces produce the torque that causes the pulley to accelerate as it rotates.

T2 * r – T1 * r = I * ?

? = a/r

T2 * r – T1 * r = I * a/r

(T2– T1) * r = I * a/r

(T2 – T1) * r^2 = I * a

I = ((T2 – T1) * r^2 )/ a ________________ (1)

Net force F = result of (b) – result of (a) = T2 – T1

Radius r = 0.170/2 = 0.085m

I’m sure you have already calculated a, still let’s calculate it again:

d = vi * t + ½ * a * t^2, vi = 0

1.26 = ½ * a * 0.790^2

a = 4.04 m/s2

Thus we have all the data, so just plug in eqn. 1 and get the final result.

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