Please, Please, Please. Answer these question only if you can answer them ALL, a
ID: 2034392 • Letter: P
Question
Please, Please, Please. Answer these question only if you can answer them ALL, and can't miss any of them, and please answer them if you are expert in them and 100% sure that your answer is correct. THIS IS VERY IMPORTANT. So with all due respect if you can't answer them ALL or skeptic about one of the answers leave them to some expert in the field.
1) A 3 kg box is released from the top of 4m high ramp with a 40 incline (angle from the ground) The coefficient of the static friction is 0.2. the coefficient of kinetic friction is 0.1 a) Draw a free body diagram with all of the forces. Label the forces. b) What is the magnitude of the acceleration of the box? c) How much work is done by friction on the box as it slides to the bottom of the ramp? d) What is the speed of the box when it reaches the bottom of the ramp? e) Does the speed at the bottom of the ramp depend on the mass of the box? SHOW or EXPLAIN why 4 a-2 and b-5 6 2) , calculate the angle between a and b 3) A 4 kg is initially at rest. Using the following graphs, determine the object's final speed a) b) Force vs Time Force vs position A 20 g bullet is fired horizontally at a speed of 50 m/s into a 300 g block of wood suspended by a rope from the ceiling. The block swings in an arc. How high above its original position does the block swing? 4) 5) Two masses (m and M) hang from a frictionless pulley What is the acceleration of the masses in terms of m and M? 6) Ball 1 (m 3 kg) is moving at 1 m/s. Ball 2 (m-1 kg) is moving at -5 m/s. After they collide, ball 1 is moving at -2 m/s. Ball 2 is moving at 4 m/s. What type of collision occurred (elastic, inelastic, or impossible)? MUST SHOW WORK TO RECEIVE CREDIT 7) A cannon fires a ball from the top to the bottom of a cliff. Ignore air resistance. Does the speed the ball at the bottom depend on the angle which it is fired? MUST SHOW WORK OR EXPLAIN TO RECEIVE CREDITExplanation / Answer
2) a = 3i + 2j + k
b = 4i + 5j + 6k
a.b = (3)(4) + (2)(5) + (1)(6)
= 28
angle = cos^-1 ( a.b/ ab)
= 28 / sqrt(3^2 + 2^2 + 1^2 ) * sqrt(4^2 + 5^2 +6^2)
= 31.48 o