Problem 8.16 Constants| Periodic Table Part A A 74 kg trampoline artist jumps ve
ID: 2038182 • Letter: P
Question
Problem 8.16 Constants| Periodic Table Part A A 74 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 3.7 m/s . (Figure 1) How fast is he going as he lands on the trampoline, 2.0 m below? Express your answer to two significant figures and include the appropriate units Figure 1 of 1 Value Units Submit Request Answer Part B If the trampoline behaves like a spring of spring constant 5.8x104 N/m, what is the distance he depress it? Express your answer to two significant figures and include the appropriate units 2.0 m Value UnitsExplanation / Answer
Part A
Using energy conservation
KEi + PEi = KEf + PEf
PEf = 0, w.r.t reference point
0.5*m*Vi^2 + m*g*h = 0.5*m*Vf^2
Vf = sqrt (Vi^2 + 2*g*h)
Vf = sqrt (3.7^2 + 2*9.81*2)
Vf = 7.3 m/sec
Part B
Again using energy conservation
KEf + PEf = KEf1 + PEf1
PEf = 0, SInce trampoline is uncompressed
KEf1 = 0, Since when max compressed, V = 0
KEf = PEf1
0.5*m*Vf^2 = 0.5*k*x^2
x = sqrt (m*Vf^2/k)
x = sqrt (74*7.3^2/(5.8*10^4))
x = 0.26 m
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