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Problem 8.16 Constants| Periodic Table Part A A 74 kg trampoline artist jumps ve

ID: 2038182 • Letter: P

Question

Problem 8.16 Constants| Periodic Table Part A A 74 kg trampoline artist jumps vertically upward from the top of a platform with a speed of 3.7 m/s . (Figure 1) How fast is he going as he lands on the trampoline, 2.0 m below? Express your answer to two significant figures and include the appropriate units Figure 1 of 1 Value Units Submit Request Answer Part B If the trampoline behaves like a spring of spring constant 5.8x104 N/m, what is the distance he depress it? Express your answer to two significant figures and include the appropriate units 2.0 m Value Units

Explanation / Answer

Part A

Using energy conservation

KEi + PEi = KEf + PEf

PEf = 0, w.r.t reference point

0.5*m*Vi^2 + m*g*h = 0.5*m*Vf^2

Vf = sqrt (Vi^2 + 2*g*h)

Vf = sqrt (3.7^2 + 2*9.81*2)

Vf = 7.3 m/sec

Part B

Again using energy conservation

KEf + PEf = KEf1 + PEf1

PEf = 0, SInce trampoline is uncompressed

KEf1 = 0, Since when max compressed, V = 0

KEf = PEf1

0.5*m*Vf^2 = 0.5*k*x^2

x = sqrt (m*Vf^2/k)

x = sqrt (74*7.3^2/(5.8*10^4))

x = 0.26 m

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