Please part A and part B! THANKS tem 1 1 of 8 tan Part A A square metal plate 0.

Question

Please part A and part B! THANKS

tem 1 1 of 8 tan Part A A square metal plate 0.180 m on each side and mass 1.22 kg is pivoted about an axis through point O at its center and perpendicular to the plate (Figure 1). Calculate the net torque about this axis due to the three forces shown in the figure if the magnitudes of the forces are F1-280 N, F2 = 14.6 N, and F's = 17.0 N. The plate and all forces are in the plane of the page. Take positive torques to be counterclockwise You may want to review (Pages 303-306) For related problemsolving tips and strategies, you may want to view a Video Tutor Solution of Applying a torque ?= 2.3 In SubmitPrev ious Answers Request Answer Figure 1 of 1 X Incorrect, One attempt remaining; Try Again 0.180 m Part B What is the angular acceleartion of the plate? rad 45° Submit Request Answer

Explanation / Answer

Torque = 17cos45*0.09 - 28*0.09 +14.6*0.09 = -0.124 Nm

Moment of inertia = I = ml^2/12 = 1.22*0.18^2/12 = 3.294*10^-3 kgm^2

So, angular acceleration = 0.124 / 3.294*10^-3 = 37.64 rad/s^2 clockwise

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