Cavemen are playing football, but they use a heavy rock instead of a football. I

Question

Cavemen are playing football, but they use a heavy rock instead of a football. If Uggh goes out for a pass running 8m/s and Puggh throws the rock with speed 16m/s at an angle of 60? with the horizontal, then can Uggh catch the rock? If he does, figure out how far (horizontally) the pass went. (Since they are using a heavy rock instead of a football it is safe to neglect air resistance.)

Confused on the steps needed to solve this. Also, I am assuming the only unknown is distance but I could be wrong.

Explanation / Answer

      Given data:                         The velocity of the Uggh, u = 8 m/s                         The velocity of the rock, v = 16 m/s                          The angle makes by rock with horizontal line, = 60o ------------------------------------------------------------------------------------------       SOLUTION:                         The horizontal distance (horizontal range) traveled by the rock can be calculated as                                          d = v2sin2/g                                              = [(16 m/s)2sin2(60o)]/(9.8 m/s2)                                              = 22.62 m/s ------------------------------------------------------------------------------------------       SOLUTION:                         The horizontal distance (horizontal range) traveled by the rock can be calculated as                                          d = v2sin2/g                                              = [(16 m/s)2sin2(60o)]/(9.8 m/s2)                                              = 22.62 m/s                                          d = v2sin2/g                                              = [(16 m/s)2sin2(60o)]/(9.8 m/s2)                                              = 22.62 m/s

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