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Two airplanes taxi as they approach the terminal. Plane 1 taxis with a speed of

ID: 2046539 • Letter: T

Question

Two airplanes taxi as they approach the terminal. Plane 1 taxis with a speed of 12.5 m/s due north. Plane 2 taxis with a speed of 6.9 m/s in a direction 18.5° north of west.
(a) What are the direction and magnitude of the velocity of plane 1 relative to plane 2?
What is the Degrees? ° north of east
What is the Magnitude in m/s

(b) What are the direction and magnitude of the velocity of plane 2 relative to plane 1?
What is the Degrees?° south of west
What is the magnitude in m/s

I Calculated Magnitude first, both were incorrect any suggestions?? For part a 10.8 magnitude I got and for b 11. Since the magnitudes were off I wanted to wait for degrees, hope someone can help :(

Explanation / Answer

what you do for this is draw a line that is labeled 12.5 going straight up and down, then you find the x component of the second plane. the equation for this is 6.9 cos(18.5) and you get 6.54. now you find the y component to add to plane 1's y component. 6.9 sin(18.5) you get 2.19. add that to 12.5 and your y is 14.69 north and 6.54 west and you use the pythagorean theorem to find the magnitude of the velocity. once you have the magnitude, you can find the direction, you do this by finding the arctangent (tan^-1) of your y/x components.