Part A. F = ? I have tried these answers below and they are wrong it says: Part

Question

Part A.

F = ?

I have tried these answers below and they are wrong

it says:

Part B.

T = ?

I have tried these answers below and they are wrong

it says:

I am so confused I really need some help.

where it says Submitted on both Part A and Part B are the answers i have tried to put in.

Please help me!!!

Submitted Evaluated Message 611 The correct answer does not depend on the variables: , , , , , . 12.0 Variables are case sensitive. Check to make sure you are using the correct case. 176 The correct answer does not depend on the variables: , , , , . 30.2 The correct answer does not depend on the variables: , . 12.0 Variables are case sensitive. Check to make sure you are using the correct case. 41.7 Variables are case sensitive. Check to make sure you are using the correct case.

Explanation / Answer

A) because there is a constant velocity you know the sum of the forces will be 0 (equilibrium)
The force F will therefore have to equal the frictional forces. Diong a FBD, the frictional forces are the product of the coefficient of friction and their weight so:

F=kgmA+kgmB

F=kg(mA+mB)

B) now the tension in the rope between the block only has to pull the block on the left at a constant rate. if this wasn't the case, block A would accelerate and the rope would either not be taught or deform/break.

F=kgmA

hope that helps

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