Everytime I do this I get a huge number but the answer is asking for in in meV.

Question

Everytime I do this I get a huge number but the answer is asking for in in meV. Please show all work and include answer as I thought I knew how to do this.

(a) Find the energy of the ground state (n = 1) and the first two excited states of a proton in a one-dimensional box of length 0.200 nm (about the diameter of a H2 molecule).
E1 = 1 . meV
E2 = 2 meV
E3 = 3 meV

Calculate the wavelength of electromagnetic radiation emitted when the proton makes a transition between the following states.

(b) n = 2 to n = 1
4 µm

(c) n = 3 to n = 2
5 µm

(d) n = 3 to n = 1
6 µm

Explanation / Answer

Are you sure about the answers you provided.
according to me answers comes out to be.
En=5*n2 mili electron volt

I.E.

E1=5mev

E2=20mev

E3=45mev

used formula

En=h2 / 8ma2 *n2

Now transaction b/w different states can be calculated as

E=hc/

your set of answers cant be right as energy of different states depend on "n2 "not "n".

hope to be helpful.

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