Now a peg is place 4/5 of the way down the pendulum\'s path so that when the mas

Question

Now a peg is place 4/5 of the way down the pendulum's path so that when the mass falls to its vertical position it hits and around the peg. As if wraps around the peg and attains its maximum height it ends a distance of 3/5 L below its starting point (or2/5L from its lowest point). How fast is the mass moving at the top of its new path(directly above the peg) in m/s And by using the original mass of m=4.8kg, what is the magnitude of the tension in the string at the top of the new path (directly above the peg) in N

Explanation / Answer

dude question is not complete i think

since the mass just attains the maximum height, the tension = 0

centrifugal force = gravitational force

mv^2/(L/5) = mg

v = (gL/5)

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