CG = m1x1 + m2x2 + m3x3/(m1 + m2 + m3) = 40kg 25m + 25kg 0.30m + 8.9kg 35m/40kg

Question

CG = m1x1 + m2x2 + m3x3/(m1 + m2 + m3) = 40kg 25m + 25kg 0.30m + 8.9kg 35m/40kg + 25kg + 8.9kg 1.9m from the right end. A 800g basketball is moving 8.5m/s [Right], and comes into contact with the backboard. It stays in contact with the backboard for 0.032s. After it bounces off the backboard it has a velocity of 6.0m/s [Left]. What was the average net force exerted on the basketball by the backboard (include direction)? F Delta t = m F = mV/ Delta t = (-6.0m/s/1/2 10.0325) F = 75N [Left].

Explanation / Answer

we have impulse = change in momentum =>f*t = m(v-u) =>f*0.032 = 0.8(8.5+6) => f= 362.5 N towards left

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