Consider the two arrangements of batteries and bulbs shown at the right. All fou
ID: 2068839 • Letter: C
Question
Consider the two arrangements of batteries and bulbs shown at the right. All four bulbs are identical and have resistance R. The two batteries are identical and maintain a potential difference (EMF) = E. Answer the following questions and explain why you believe your answer. (Most bulbs are brighter when there is more current through them. Assume that is the case for these bulbs.) (a) In system 1, which bulb is brighter? (b) In system 1, what is the current through each bulb, the voltage drop across each bulb, and the power dissipated by each bulb? (c) In system 2, which bulb is brighter? (d) In system 2, what is the current through each bulb, the voltage drop across each bulb, and the power dissipated by each bulb? (e) Which bulbs are brighter, those in system 1 or those in system 2? (f) If one bulb in each system burns out, will the other go out as well? Why? If the other bulb doesn't go out will it get brighter or stay the same when the first bulb in the circuit burns out?
Explanation / Answer
in system 1, A ) both bulbs A and B will have same brightness bcoz they are connected in series and in combined state they will the effect of effective emf on them which wud be same for both. current, voltage drop and power dissipated will be same IN BOTH THE CASES, current I = E/R and Power P= E^2/R, B) in system two, again both will glow with same brightness but will be more brighter than the case of system 1. system 2 bulbs will be brighter than system 1. C) if in system 1, one bulb burst out, the second or the rest will not glow, but in system2 in one bulb burst, the remaining bulbs continue to glow