For the following data: Make a scatterplot of y versus x Is the relationship bet
ID: 2079153 • Letter: F
Question
For the following data: Make a scatterplot of y versus x Is the relationship between x ami v approximately linear, or is it nonlinear? Compute the natural logarithm of each y value This is known as making a Jog transformation of v Make a scattershot of In(y) versus Is the relationship between x and In(y) approximately linear, or is it nonlinear. In general, it is easier to work with quantities that have an approximate linear relationship than with quantities that have a nonlinear relationship. For this example, do you think it would be easier to work with x and y or with x and in(y)? Explain A vendor converts die weighs on packages she sends out from pounds to kilograms (1 kg) How does this affect the standard deviation of the weighs? How does this affect the mean of weight of the packages? If the vendor begins using heavier packaging which increases the weight of each package by 50 g How does this affect the mean weight and standard deviation of the weights?Explanation / Answer
Due to chegg policy we can solve only one question at once
Question 1:
a)
x=[1.4,2.4,4.0,4.9,5.7,6.3,7.8,9.0,9.3,11.0];
y=[2.3,3.7,5.7,9.9,6.9,15.8,15.4,36.9,34.6,53.2];
scatter(x,y);
As we can observe It is not a linear graph.
b)
x=[1.4,2.4,4.0,4.9,5.7,6.3,7.8,9.0,9.3,11.0];
y=[2.3,3.7,5.7,9.9,6.9,15.8,15.4,36.9,34.6,53.2];
y1=reallog(y);
scatter(x,y1);
We can observe that we obtain an approximately a linear graph for ln(y) vs x.
c)
It is easier to work with quantities having linear relationship as they have a direct proportional relation with each other and hence it is easy to fing the values of one term using the other term whereas for non linear relationship we need to find the relation between the quantities using some boundary conditions which becomes difficult for large quantities.
In this case it is easier to work with x and ln(y) ass they have a linear relationship.