Please explain this circuit to me in more detail. 1. What inputs go in A and B 2
ID: 2083649 • Letter: P
Question
Please explain this circuit to me in more detail.
1. What inputs go in A and B
2. if I have a 6 digit binary, how will I input it?
BIT SERIAL BINARY -TO BCD CONVERTER HIGH HIGH LOW Q1 Q2 Q3 Ao Bo A1 B1 A2 B2 A3 B3 Ao Bo A1 B1 A2 B2 A3 B3 3383 7483 9383/7483 4-BIT BINARY C4 Co Co 4-BIT BINARY C4 FULL ADDER FULL ADDER S2 S3 So S2 S3 PE Po P P2 P3 PE Po P1 2 P3 9300 9300 TO NEXT STAGE BINARY IN CP4 BIT UNIVERSAL O3 P4-BIT UNIVERSAL Q3 o MSB FIRST ol SHIFT REGISTER SHIFT REGISTER MR Qo Q1 Q2 Q3 MR Q0 Q1 Q2 Q3 BCD OUT BCD OUT-LSD The reverse of the BCD-to-binary algorithm is used for nto the parallel data inputs. By adding 11 and then ig binary-to-BCD conversion. The binary word is shifted noring the most significant bit, the same 4-bit adder also detected whether or not the correction is necessary. most significant bit first, into a shift register consisting of several series-connected 9300s. Each shift doubles A binary number is completely converted when its LSB the contents of the registers in terms of BCD notation has been shifted in, but the shift register must be long enough to hold the BCD result, always longer than the Therefore, a correction is required whenever any of the binary number. This circuit can be used for any number 4-bit registers contains a number greater than four, of bits and digits. It requires only one 93004-bit shift which when shifted generates a non-BCD code. This register, one 9383 4-bit adder, and one inverter for each correction is performed by adding three to the contents of the register and inserting the sum one bit downstream resulting BCD digit.Explanation / Answer
Right, I began studying electronics about half a month ago or so and I've run into a bit of a problem.
I've come to the point where I want to create my first processor. Mind you, it's going to be rather small (can only add two 3-bit numbers and save them both in memory).
For this I decided to use 5 buttons. 3 for each bit and 2 to save the numbers. My memory would be comprised by 3 D flip-flops for both numbers. From there, I'd use a Full Adder to get the sum of the numbers and from there show the numbers on an indicator.
However, there's the problem. The Decoder that I use can only decode numbers in binary that are up to 9. Once the sum is over that amount, the indicator doesn't show anything.
From there, I realised that I'd need a circuit to actually convert the Binary to BCD so that I could show the number on my indicators instead of having blank ones. I've been searching for a Binary to BCD converter for the past few days and I have found something. One of the things I found was a rather outdated circuit that is not being made anymore, which is the DM74185A. Since this is obviously not an option, I kept searching until I found a converter made of Full Adders and Shift Registers.