In the circuit in the figure below, the batteries have negligible internal resis

Question

In the circuit in the figure below, the batteries have negligible internal resistance. (Take R1 = 3. 05 Ohm , R2 = 3. 60 Ohm , and R3 = 5. 70 Ohm . ) Find the magnitude of the current in each resistor Find the magnitude of the potential difference between points a and b. Find the power supplied by each battery, left battery

Explanation / Answer

12 = 3.05 I1 + 5.7(I1+I2) and 12 = 3.6 I 2 + 5.7 (I1+I2) => 3.05 I1=3.6I2 => I1= I3.05=0.8837 and I2=I3.6 = 0.74869 and I5.7 = I1+I2=1.63239 and Vab = R3(I5.7)=9.3 V power supplied by left battery = VI3.6 = 8.98428W and by right battery = V (I3.05)=10.6044W

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---