Please do not answer this question without the steps needed to solve it. I have

Question

Please do not answer this question without the steps needed to solve it. I have the answers; I am looking for an explanation that I can follow. I know the answers are 0.421 m/s and 0.237 Joules.

The question is. A 5.00 kg squid initially at rest ejects 0.250 kg of fluid with a velocity of 10.0m/s. What is the recoil velocity of the squid if the ejection takes 0.100 seconds and there is a 5.0 kg frictional force opposing the squid's movement. Also, how musch energy is lost to work done against the friction.

Explanation / Answer

conserving momentum

2.5*10 = 4.75*u

u = 0.526 m/s

now

impulse = F*dt = change in momentum

5*0.1 = 4.75*0.526 - 4.75*v

v = 0.421 m/s

so recoil vel = 0.421 m/s

energy lost = 1/2*m*(0.526^2 - 0.421^2 ) = 0.236 J

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