Part A Determine the position of the object. s=? Part B Determine the size of th

Question

Part A Determine the position of the object. s=? Part B Determine the size of the object. |y|=? Part C Is the image erect or inverted? Part D Are the object and image on the same side or opposite sides of the lens? Part A Determine the position of the object. s=? Part B Determine the size of the object. |y|=? Part C Is the image erect or inverted? Part D Are the object and image on the same side or opposite sides of the lens? Part B Determine the size of the object. |y|=? Part C Is the image erect or inverted? Part D Are the object and image on the same side or opposite sides of the lens? Part C Is the image erect or inverted? Part D Are the object and image on the same side or opposite sides of the lens? Part D Are the object and image on the same side or opposite sides of the lens?

Explanation / Answer

a) 1/i + 1/o = 1/f

B) magnification = I/O = -v/u

= -(-16.2/7.21) =2.246 = I/O =0.79/O which gives O = 0.351cm = 3.51 mm = object length


C) m>0 so erect

D) since virtual image they are on the same side

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