A cylinder contains 3.09 mol of helium gas at a temperature of 289 K. The molar

Question

A cylinder contains 3.09 mol of helium gas at a temperature of 289 K. The molar specific heat of helium at con- stant volume is 12.5 J Kmol. How much heat must be transferred to the gas to increase its temperature to 584 K if it is heated at constant volume? A cylinder contains 3.09 mol of helium gas at a temperature of 289 K. The molar specific heat of helium at con- stant volume is 12.5 J Kmol. How much heat must be transferred to the gas to increase its temperature to 584 K if it is heated at constant volume?

Explanation / Answer

no of moles n =3.09

molar specific heat of helium at constant volume Cv=12.5 J/Kmol

T1=289

T2=584 K

amount of heat required dQ=nCv(dT) =nCv(T2-T1)=3.09*12.5x(584-289)=1.139x10^4 J=11394.37 J

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