Part 1 - Recognize the Principles Part 2 - Identify the Relationships n 1 sin θ

Question

Part 1 - Recognize the Principles

Part 2 - Identify the Relationships

n1 sin θ1 = n2 sinθ2 n1θ1 = n2θ2 n1 sin θ2 = n2 sinθ1 tan θ1 = 2.0 L tan θ1 = L 2.0 sin θ1 = L 2.0 tan θ2 = h1 L2 tan θ2 = L2 h2 = Lh1 h2 tan θ2 = L2 h2 = L(h1/2.0 m) h2

Part 3 - Solve

Calculations Using the geometrical relations from Part 2, you can solve for n1, the index of refraction of the liquid. What is the value of n1?
n1 =
Using the geometrical relations from Part 2, you can solve for n1, the index of refraction of the liquid. What is the value of n1?
n1 =
2.0 L

Explanation / Answer

I will give you a hint as I believe thinking the solution out yourself is more interesting. You probably know the equation of refraction n1*sin(a)=n2*sin(b) In this case n1 is the refraction index of water and n2 the same for air. Also from this you should assume that n1>n2 . To be more exact n1=4/3 and n2=1 The former equation can be written as n1/n2*sin(a)=sin(b) Now you should think what if n1/n2*sin(a)>1 Thus if a is smaller then a certain value then the equation makes sense but if it is bigger then it then it does not. This probably has a physical meaning. After that you have to also know a thing ot two about a triangle with one angle 90 deg If you are still in trouble after this then I can also give other hints or the full solution. For checking if your solution is right the answer is D=7,03 m

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