Consider two parallel-plate capacitors identical in shape, one aligned so that t
ID: 2110748 • Letter: C
Question
Consider two parallel-plate capacitors identical in shape, one aligned so that the plates are horizontal (Figure 1) , and the other with the plates vertical (Figure 2) .
c.) What is the electric field between the plates of the capacitor without dielectric?
d.) The horizontal capacitor is filled halfway with a material that has dielectric constant 3.28. What is the new capacitance of the capacitor?
e.) The vertical capacitor is filled halfway with a material that has dielectric constant 3.28. What is the new capacitance of the capacitor?
Explanation / Answer
a. C= eoA/d
C=8.85*10^-12*1.97*10-^-2/4.2*10^-3
C=4.15*10^-11 F
b.Q=CV=4.15*10^-11*84.1=349.1*10^-11 C
c.E=V/d=84.1/4.2*10^-3=20.02 .
D.C=(K1k2(K!+K2) eoA/d
c= 3.28/4.28* 4.15*10^-11 F
c=3.18*10^-11F
E.C=(K1k2(K!+K2) eoA/dc= 3.28/4.28* 4.15*10^-11 F
c=3.18*10^-11F