Figure is an edge-on view of a 16cm diameter circular loop rotating in a uniform

Question

Figure is an edge-on view of a 16cm diameter circular loop rotating in a uniform7.9*10^-2 T magnetic field.

Part A

What is the magnetic flux through the loop when is 0 degrees ?

Express your answer to two significant figures and include the appropriate units.
=
Part B
What is the magnetic flux through the loop when is 30 degrees ?
Express your answer to two significant figures and include the appropriate units.
=

Part C
What is the magnetic flux through the loop when is 60 degrees ?
Express your answer to two significant figures and include the appropriate units.
=

Part D
What is the magnetic flux through the loop when is 90 degrees ?
Express your answer to two significant figures and include the appropriate units.

Explanation / Answer

Given that radius of the loop is r = 0.08 m magnetic field is B = 7.9*10^-2 T a ) Magnetic flux through the loop at 0 degrees is     phi = BA cos 0        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 0 = 1.59*10^-3 Wb b ) Magnetic flux through the loop at 30 degrees is     phi = BA cos 30        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 30       = 1.375*10^-3 Wb c ) Magnetic flux through the loop at 60 degrees is     phi = BA cos 60        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 60       = 7.94*10^-4 Wb d ) Magnetic flux through the loop at 60 degrees is     phi = BA cos 60        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 90      = 0        phi = BA cos 60        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 60       = 7.94*10^-4 Wb d ) Magnetic flux through the loop at 60 degrees is     phi = BA cos 60        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 90      = 0        phi = BA cos 60        = 7.9*10^-2 T * 3.14 (0.08m)^2 cos 90      = 0   

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