help The figure below shows the horizontal forces acting on a sailboat moving no
ID: 2115428 • Letter: H
Question
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The figure below shows the horizontal forces acting on a sailboat moving north at constant velocity, seen from a point straight above its mast. At the particular speed of the sailboat, the water exerts a = 351-N drag force on its hull and theta = 38.0 degree. For each of the situations (a) and (b) described below, write two component equations representing Newton's second law. Then solve the equations for P (the force exerted by the wind on the sail) and for n (the force exerted by the water on the keel). Choose the x direction as east and the y direction as north. n = N p = N Now choose the x direction as theta = 38.0 degree north of east and the y direction as theta = 38.0 degree west of north. n = N p = N Compare your solutions to part (a) and (b). Do the results agree? Yes No A high diver of mass 71.0 kg jumps off a board 10.0 m above the water. If his downward motion is stopped 2.40 s after he enters the water, what average upward force did the water exert on him? kNExplanation / Answer
P cos theta = n
351 cos 38 = n
n = 276.59 N
Psin theta = F
F = 351 sin38
F = 216.09 N
case 2
takinh the components of F and n
nsin38 = F cos 38
0.78 n = F
P - ncos38 - Fsin38 = 0
351 - 0.788n - 0.48n =0
n = 276.8 N
F = .78 x 276.8 = 215.91 N
there is no change in the values
the slight change is due to rounding off of the results as various stages.
the values remain the same in both cases