A 3cm object is 20cm to the left of a diverging (first) lens with a focal length

Question

A 3cm object is 20cm to the left of a diverging (first) lens with a focal length of 10cm.

A)What is the location of the image?

B)What is the height of the image?

C)The image is:

a.       Real, Upright

b.      Real, Inverted

c.       Virtual, Upright

d.      Virtual, inverted

15 cm to the right of the first lens is a converging lens with a focal length of 5cm.

A)     What is the location of the second image (from the second lens)?

B)      What is the height of the second image

C)      With respect to the original object, the second image is:

a.       Real, upright

b.      Real, inverted

c.       Virtual, upright

d.      Virtual, Inverted

Explanation / Answer

1)

given data

y = 3cm
u = 20cm
f = 10cm

A)1/u + 1/v = 1/f

==> v = u*f/(u-f) = 20 cm

B) y'/y = v/u ===> y' = 20/20 * 3 = 3 cm


C) a Real,upright

2) given data is insufficient.

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