In the circuit shown, the AC voltage source supplies an rms voltage of 115 V and
ID: 2121139 • Letter: I
Question
In the circuit shown, the AC voltage source supplies an rms voltage of 115 V and the circuit has R1 = 3.35 k%u03A9 and L = 36 mH.
A)
f=
B)
VrmsR=
C)
VrmsL=
D)
VrmsTotal=
E)
Consider a RC circuit where the capacitance is 57 %u03BCF, the maximum current is 2.7 A and the frequency of the generator is 75. The phasor diagram for the current and voltage in this circuit is shown to the left. At some instant of time, the current into the capacitor is 0.8 A and increasing.
A)
%u0398=
B)
Vmax=
C)
Vmax=
D)
Vinstant=
Explanation / Answer
A)
X = V/I = 115/(31.33/1000) = 3670.60325566 ohms
X = sqrt(R^2 + (1/wL)^2)
=>3670.60325566 = sqrt(3350*3350 + (wL)^2)
=> wL = 1500.27606142
thus w*36/1000 = 1500.27606142
=> w =41674.335039
2*3.14*f = 41674.335039
=> f = 6636.0406 Hz answer
B)
potential drop = V*R/sqrt(R^2+wL^2) = 115*3350/(sqrt(3350*3350) + (1500.27606142*1500.27606142)) = 104.9555 V answer
C)potential drop = V*wL/sqrt(R^2+wL^2) = 115*1500.27606142/(sqrt(3350*3350) + (1500.27606142*1500.27606142)) = 47.003649 V answer
D) Vrms total = 115 V
E)power = I^2*X = 36*36*3670.60325566/1000000 = 4.75710181933536 W