4.28 nm You are correct. Previous Tries style=\"cursor: pointer;\"> What is the

Question

4.28 nmYou are correct.Previous Triesstyle="cursor: pointer;">

What is the energy of the Hydrogen atom when the electron is in the n = 5 state?style="color: rgb(0, 51, 153); font-family: verdana, arial, helvetica, sans-serif; font-size: large; line-height: 16px;">style="color: rgb(0, 51, 153); font-family: verdana, arial, helvetica, sans-serif; font-size: large; line-height: 16px;">style="color: rgb(0, 51, 153); font-family: verdana, arial, helvetica, sans-serif; font-size: large; line-height: 16px;">style="color: rgb(0, 51, 153); font-family: verdana, arial, helvetica, sans-serif; font-size: large; line-height: 16px;">name="04">

Explanation / Answer

a)radius = n^2 *0.529 A = 81*0.529 = 4.2849 nm

b)E = -13.6/n^2

E = -13.6/25 = 0.544 eV = -0.8704 *10^-19 J

Related Questions

Navigate

• Browse (All)
• Browse 4
• Subjects