Bob Leave Memphis at 8:00 a.m. to drive to Johnson city,400 mi away. He travel a
ID: 2125300 • Letter: B
Question
Bob Leave Memphis at 8:00 a.m. to drive to Johnson city,400 mi away. He travel at a steady 50 mph. Bill leave Memphis at 9:00 a.m and drives a steady 60mph.
Who get to Johnson city first?
How long does the first to arrive have to wait for the seconds?
I know the answers, bill get their first and he had to wait 20 minutes.
I drew a chart and it took me a while to get the answer. I want to know how to set it up with the KINEMATIC EQUATION
How do I use Uniform method where as Sf=Si+V*t
Sf= final position
Si=initial position
V= velocity
t=time
Explanation / Answer
bob takes time=400/50=8 hours
bill takes time=400/60=6.67 hours
so bob's time of arrival=8+8=16:00 hrs
bill's arrival time=9+6.67=15:40 hrs
so bill arrives early
b)bill has to wait for 20 minutes.
formula used=distance=veloicty*time
as velocity is uniform,acceleration=0