Charge is distributed over the surface of a circle of radius a lying in the xy p
ID: 2128092 • Letter: C
Question
Charge is distributed over the surface of a circle of radius a lying in the xy plane with origin at the center. The surface density is given in cylindrical coordinates by where A is a constant. What are the units of A? What is the total charge on the circle? Find the force produced by this charge distribution on a point charge located on the z axis.
Can someone tell me if I'm in the right direction? Also, could you help me out solving the integral? Did I make any mistake?
Charge is distributed over the surface of a circle of radius a lying in the xy plane with origin at the center. The surface density is given in cylindrical coordinates by o= Ap^2 where A is a constant. What are the units of A? What is the total charge on the circle? Find the force produced by this charge distribution on a point charge located on the z axis.Explanation / Answer
Gauss's law for electric field (E):
E?dA = (q in) / (?0)
E = ke q / r2
E = 0 inside a CONDUCTOR
q = ?dA (surface area?)
q = ?dV (volume? )
So...
for r < a, the electric field is not 0 and so
E ? dA = q in / ?0
E (4?r2) = q in / ?0
E = q in / (4?r2?0)
which turns out wrong for r < a. It is still wrong even when I substitute q in as p2. Relevant equations
Gauss's law for electric field (?):
E?dA = (q in) / (?0)
E = ke q / r2
E = 0 inside a CONDUCTOR
q = ?dA (surface area?)
q = ?dV (volume? )
3.
for r < a, the electric field is not 0 and so
E ? dA = q in / ?0
E (4?r2) = q in / ?0
E = q in / (4?r2?0)
which turns out wrong for r < a. It is still wrong even when I substitute q in as pV.
Force = Eq