Consider three force vectors F1 with magnitude 31 N and direct 58 degress, F2 wi
ID: 2129879 • Letter: C
Question
Consider three force vectors F1 with magnitude 31 N and direct 58 degress, F2 with magnitude 28 N and direction -120 degress, F3 with magnitude 15 N and direction 150 degress. all direction angles theta are measured from the positive x axis : counter clockwith for theta > 0 and clockwise for theta < 0
what magnitude F of the net force vector F= F1+F2+F3? anwser in units of N
b.) what is the direction of F as an angle between the limits of -180 and +180 from the positive x axis with counterclockwise as the positve angular directs and in units of degree
Explanation / Answer
a) add components
x = 31*cos(58) + 28*cos(-120) + 15*cos(150)=-10.56
y = 31*sin(58) + 28*sin(-120) + 15*sin(150)=9.54
mag = sqrt(10.56^2+9.54^2)=14.23 N
b) direction = arctan(9.54/-10.56)=137.91 degrees