Can someone solve Part a and b? A muon is created by a cosmic-ray interaction at
ID: 2132343 • Letter: C
Question
Can someone solve Part a and b?
A muon is created by a cosmic-ray interaction at an altitude, of 60 km. Imagine that a speed of 0.998, as measured by a ground-based observer. After the muon's "internal clock" registers 2.0mus (which is a. bit longer than the average life of a muon), the muon decays. If the Moun's internal clock were to measure the same time between its birth and death as clocks on the ground do (i.e., special relativity is not true and time is universal and absolute), about how far would this muon have traveled before it decayed? How far will this muon really travel before. it decays?Explanation / Answer
a)
L = v t = 0.998*3e8 * 2e-6 = 599 m
b)
t = gamma tp = tp/(1 - (v/c)^2)^0.5 = 2e-6/(1 - 0.998y2)y.5 = 3.1639e-5 s
L = v t = 0.998 *3e8 * 3.1639e-5 = 9470 m