A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its

Question

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the rim is constant and equal to 7.80 m/s.

A Ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The linear speed of a passenger on the rim is constant and equal to 7.80 m/s. What are the magnitude and direction of the passenger's acceleration as she passes through the lowest point in her circular motion? What are the magnitude and direction of the passenger's acceleration as she passes through the highest point in her circular motion?

Explanation / Answer

a) a = v^2/r = 4.35 m/s2 upward toward the centerdownward

b) a = v^2/r = 4.35 m/s2 downward toward the center

C) t = 2 x pi x r / v   = 11.28 sec

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---