Please i need the answer urgently <<< thanks in advance A small airplane flying

Question

Please i need the answer urgently <<< thanks in advance

A small airplane flying horizontally with a speed of 300 km/h at an altitude of 120 m above a remote valley drops an emergency medical package at A. The package has a parachute which deploys at B and allows the package to descend vertically at a constant speed of 1.8 m/s. If the drop is designed so that the package is to reach the ground 37 seconds after release at A, determine the horizontal lead L so that the package hits the target.

Explanation / Answer

v = 300*5/18 = 83.33 m/s

let t1 is the time taken to reach from A to B

L = v*t1

distance traveleed in y-direction in time t1

s1 = voy*t1 + 0.5*g*t^1 = 0 + 0.5*9.8*t1^2

s1 = 4.9*t1^2

distance travelled in t2=(37-t1) time

s2 = 1.8*t2

s2 = 1.8*(37-t1)

s2 = 66.6 - 37*t1

we know, s1+s2 = 120 m

4.9*t1^2 -37*t1 - 53.4 = 0

solving above equation we get, t1 = 8.64 s

so, L = v*t1 = 83.33*8.64 = 720 m

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