Consider three identical metal spheres, A, B, and C. Sphere A carries a charge o
ID: 2134012 • Letter: C
Question
Consider three identical metal spheres, A, B, and C. Sphere A carries a charge of +4q. Sphere B carries a charge of -q. Sphere C carries no net charge. Spheres A and B are touched together and then separated. Sphere C is then touched to sphere A and separated from it. Lastly, sphere C is touched to sphere B and separated from it. (a) What is the ratio of the final charge on sphere C to q? What is the ratio of the final total charge on the three spheres to q (b) before they are allowed to touch each other and (c) after they have touched?
Explanation / Answer
the charges will equalize so they balance
total charge of the 3 spheres together is 3q
when A touches B the net charge between them is 3 so 1.5q stays on A and 2.5q goes onto B leaving B at 1.5 q
when you touch A to C ... A has 1.5 q and C has 0 so total is 1.5 q that means A will have 0.75q and C will gain 0.75q.....
C= 0.75q and B= 1.5q touch and then total charge is 2.25q so C would gain 0.375q and B would loose 0.375q so each would be left with C = B = 1.125q
a) C/q = 1.125
b) not sure what you mean final total charge is same its 3
A = 0.75q ... B = C = 1.125q
so adding them adds to 3
the total charge has to be the same