A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This paralle
ID: 2136371 • Letter: A
Question
A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This parallel group is connected in series with a 29.3-? resistor. The total combination is connected across a 16.4-V battery. Find (a) the current and (b) the power dissipated in the 131.7-? resistor.
A 60.3-? resistor is connected in parallel with a 131.7-? resistor. This parallel group is connected in series with a 29.3-? resistor. The total combination is connected across a 16.4-V battery. Find (a) the current and (b) the power dissipated in the 131.7-? resistor.Explanation / Answer
net R = 29.3 + ( 60.3*131.7/60.3+131.7) = 70.36 ohms
i = 16.4/70.36 = 0.233 amp
power dissipated = V*V /r = 0.69585 watts