Suppose the roller coaster in the figure ( h 1 = 35 m, h 2 = 13 m, h 3 = 25 ) pa

Question

Suppose the roller coaster in the figure (h1 = 35 m, h2 = 13 m, h3 = 25) passes point A with a speed of 3.30 m/s. If the average force of friction is equal to one fifth of its weight, with what speed will it reach point B? The distance traveled is 50.0 m.

Suppose the roller coaster in the figure (h1 = 35 m, h2 = 13 m, h3 = 25) passes point A with a speed of 3.30 m/s. If the average force of friction is equal to one fifth of its weight, with what speed will it reach point B? The distance traveled is 50.0 m.

Explanation / Answer

K.E. at B + P.E at B + loss of energy due to friction = K.E. at A + P.E. at A

mv^2 /2 + 0 + 50 x mg/2   = m x 3.3^2/2 + mg x 35

v = 14.38 m/s

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