In procedure 1: suppose the hanging mass is mH = 275 g and the mass of the cart

Question

In procedure 1: suppose the hanging mass is mH = 275 g and the mass of the cart is mC = 924 g. Assume there is no friction anywhere in the system, and the system starts at rest. Use g = 9.81 m/s2.

a) Find the acceleration of the system.

  m/s2

b) Find the tension in the string.

  N

c) If the track has length L = 3.04 m, find vf, the speed of the cart just before it hits the barrier.

  m/s

In procedure 1: suppose the hanging mass is mH = 275 g and the mass of the cart is mC = 924 g. Assume there is no friction anywhere in the system, and the system starts at rest. Use g = 9.81 m/s2. Find the acceleration of the system. Find the tension in the string. If the track has length L = 3.04 m, find vf, the speed of the cart just before it hits the barrier. m/s

Explanation / Answer

As ths string is being stretched on inextensible pulley, the tension(T) in string will be same and both the masses will move with same acceleration.(a)

Developing equation :

mH(g) - T = mH(a)

T = mC(a)

solving the above equation we get,

mH(g) - mC(a) = mH(a)

putting teh valuues

(0.275)(9.8) - (0.924)(a) = 0.275)(a)

a= 2.245 m/s^2 apprx------aceelertaion

T = (0.924)(2.245)= 2.076 N apprx---Tecsion

Using teh kineamtic quation,

v^2 - u^2 = 2as

v^2- 0 = 2( 2.245)(3.04)

v= velocity before it hits = 3.69 m/s apprsx

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