Question
Here is the question
Using the equation U1 + K1 + W other = U2 + K2, i.e., the Principle of the Conservation of Energy, solve the following problem. A mass of 0.500 kg is attached over a massless pulley to a mass of 100g as shown below. Starting from rest at the top of the 45.0degree incline shown, it is given a small tap (to break any residual forces of static friction), and moves under sliding friction (muk = 0.200) down the incline. After travelling 2.00 m, it encounters a spring (k = 45.0 N/m) in its equilibrium position. How fast is the half- kilogram mass moving once it has moved 220 cm from its starting position? Your answer should be accurate to 3 significant figures.
Explanation / Answer
E1 = E2
0.5*9.81*2.2*sin(45) - 0.2*0.5*9.81*cos(45)*2.2 = 1/2*(0.5+0.1)*v^2 + 0.1*9.81*2.2 + 0.5*45*.2^2
v=3.19 m/s