Particle A of charge 2.91 times 10-4 C is at the origin, particle B of charge -5
ID: 2141169 • Letter: P
Question
Particle A of charge 2.91 times 10-4 C is at the origin, particle B of charge -5.88 times 10-4 C is at (4.00 m, 0), and particle C of charge 1.07 times 10-4 C is at (0, 3.00 m). We wish to find the net electric force on C.(a) What is the x component of the electric force exerted by A on C.(b) What is the y component of the force exerted by A on C.c) Find the magnitude of the force exerted by B on C.(d) Calculate the x component of the force exerted by B on C.e) Calculate the y component of the force exerted by B on C f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C .g) Similarly, find the y component of the resultant force vector acting on C.(h) Find the magnitude and direction of the resultant electric force acting on C.Explanation / Answer
http://academicservices.us/ can help you with your homework when stuck