Replace the loading shown by an equivalent single resultant force and specify th

Question

Replace the loading shown by an equivalent single resultant force and specify the x and y coordinates of its line of action. Assume F1= 140N and F2= 240N .

a) Detrermine the resultant force.

b) Determine the

x and y coordinates of the its line of action.

Replace the loading shown by an equivalent single resultant force and specify the x and y coordinates of its line of action. Assume F1= 140N and F2= 240N . Determine the resultant force. Determine the x and y coordinates of the its line of action.

Explanation / Answer

for equivalent force:

let us assume the x and y directions as positive

resultant force = 2*(F1 + F2) = 2*(140+240) = 380*2 = 760

So, for coordinates

X coordinate = (2*F2 + 3F1 + 3F1 - 3F2)/ total force = (6F1-F2)/760 = (6*140-240)/760 = 600/760 = 0.79m

Y coordinates = (3*F1 - 3F1 - 2F2 - 2F2)/760 = (-2F2)/760 = -2*240/760 = 0.63m

a)

resultant force = 760N ( as calculated above)

b)

X coordinate is 0.79m

Y coordinate is 0.63m

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