The diagram below represents the results of an electrophoretic analysis of hemog
ID: 214360 • Letter: T
Question
The diagram below represents the results of an electrophoretic analysis of hemoglobin A (Hb A), sickle cell hemoglobin (Hb S), and blood samples for three individuals (I #1,1 12, 1# 3). HDS Hb A1#11#2 1#3 1) What is the phenotype of Individual #2 (1 #2)? a) normal b) has sickle cell anemia -2) What is the complete genotype of unknown individual #1? (Allele symbols: HBAi-normal - alpha subunit allele; HBB- normal beta subunit allele; HBS-sickle cell allele.) a) HBA1/HBA1 HBB/HBS b) HBA1/HBA1 HBS/HBS c) HBA1/HBA1 HBB/HBB d) HBAS/HBA1 HBB/HBS 3) How would changing the electrophoresis buffer to a pH of 6 affect the overall charge of a protein a) At pH 6, more R groups on the amino acid side chains would be positively charged, making the b) At pH 6, more R groups on the amino acid side chains would be negatively charged, making the c) At pH 6, more R groups on the amino acid side chains would be positively charged, making the d) At pH 6, more R groups on the amino acid side chains would be negatively charged, making the compared to a buffer of pH 9.2? overall protein's charge more positive. overall protein's charge more negative. overall protein's charge more negative. overall protein's charge more positive.Explanation / Answer
1) since the band of the individual 2 corresponds to the band of a person with HbA , individual 2 has normal phenotype.
2) HbA1/HbA1 HbS/HbS (b)
3) At a lower pH more hydrogen ions are available and the side chains of the amino acids are protonated as a result giving the residue a positive charge
Thus a is correct