Please, details included would be appreciated. (not just the answer) Three long
ID: 2143866 • Letter: P
Question
Please, details included would be appreciated. (not just the answer)Three long wires are each carrying currents. The wires at A (x=+4m, y=+3m) and at the origin (O) carry currents of 50A into the page. The wire at C (x=+4m, y=?3m) carries a current of 30A out of the page. a) Find the magnitude and direction of the force on a 0.5m length of the wire at the A exerted by each of the wires at the origin, O, and at C.
b) Find the magnitude and direction of the total force on a 0.5m length of the wire at A.
Please, details included would be appreciated. (not just the answer)
Three long wires are each carrying currents. The wires at A (x=+4m, y=+3m) and at the origin (O) carry currents of 50A into the page. The wire at C (x=+4m, y=?3m) carries a current of 30A out of the page. a) Find the magnitude and direction of the force on a 0.5m length of the wire at the A exerted by each of the wires at the origin, O, and at C.
b) Find the magnitude and direction of the total force on a 0.5m length of the wire at A.
Explanation / Answer
r1 = sqrt(3^2+4^2) = 5
angle =tan^-1(3/4) = 36.86
a) due to origin B1 = uo*I /(2*pi*r1) = 4*pi*10^-7*50 /(2*pi*5) = 2*10^-6 T making angle 36.86 with x axis in clockwise direction
F1 = B1*I*L = 2*10^-6*50*0.5 = 50e?6 N
B2 = uo*I /(2*pi*r2) = 4*pi*10^-7*50 /(2*pi*6) = 1.67*10^-6 T alox -x ais
F2 = 41.75 *10^-6 N
b) Fnet = sqrt(F1^2+F2^+2*F1*F2*cos(90+36.86)) = 41.69 *10^-6 N
direction = 163.62 counter clock wise with +xaxis