A small block of mass 45 g (.450kg) is released from rest at the top of a curved

Question

A small block of mass 45 g (.450kg) is released from rest at the top of a curved frictionless wedge of mass 206 g (.206kg) which sits on a frictionless horizontal surface as shown.

The acceleration due to gravity is 9.81 m/s2. Right is the positive direction.

When the block leaves the wedge, its velocity is 4.04 m/s to the right.

I found that the velocity "vb" of the wedge after the block reaches the horizontal surface is -.8825

What is the height h of the wedge? Answer in units of m

I keep getting .83188 by using H=v1^2/2g and it says its wrong...Thanks!

I don't have access to the picture right now but it has the small mass on top and the 2nd mass is sort of like a sloping hill (with just the right hall shown)

Explanation / Answer

by momentum banace

45*4.04=206*v

==> v=0.8825 m/s

by energy balance

mgh=1/2(0.045*4.04^2 +0.206*0.8825^2)

==> h=0.4474/(0.045*9.8)=1.0145 m

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