Two square conducting loops carry currents of 5.4 A (on the left) and 3.4 A (on
ID: 2144087 • Letter: T
Question
Two square conducting loops carry currents of 5.4 A (on the left) and 3.4 A (on the right) as shown in Fig. 30-49 (please use these values of the currents instead of those shown in the figure). What is the value of the integral of B?l (sign and magnitude) for each of the two closed paths shown?
Path 1:
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Path 2:
( )
Two square conducting loops carry currents of 5.4 A (on the left) and 3.4 A (on the right) as shown in Fig. 30-49 (please use these values of the currents instead of those shown in the figure). What is the value of the integral of B?l (sign and magnitude) for each of the two closed paths shown?Explanation / Answer
a)
integral [B ds] =uo*I
Intagral[B ds]=(4pi*10^-7)(-5.4+3.4)
integral[Bds] =-2.51*10^-6
b)
Intagral[B ds]=(4pi*10^-7)(-5.4-5.4-3.4)
Intagral[B ds]=1.78*10^-4 or 178*10^-6