In the diagram disk 1 has a moment of inertia of In the diagram disk 1 has a mom

Question

In the diagram disk 1 has a moment of inertia of

In the diagram disk 1 has a moment of inertia of 4.4 kg m2 and is rotating in the counterclockwise direction with an angular velocity of 7.1 rad/s about a frictionless rod passing through its center. A second disk rotating clockwise with an angular velocity of 9.3 rad/s falls from above onto disk 1. The two then rotate as one in the clockwise direction with an angular velocity of 1.8 rad/s. Assume there is no friction between the two disks. Determine the moment of inertia of disk 2.

Explanation / Answer

Conservation of Angular momentum:

I is moment of Inertia.

w is angular velocity.

I1w1 + I2w2 = I3w3

Here w1 and w2 have opposite sense.(Clockwise and counter clockwise)

Let clockwise be positive and vice versa.

I3= I1 + I2

I1w1 + I2w2 = I3w3 .......... (4.4 x -7.1) + (I2 x 9.3) = (4.4 + I2)x1.8

Solving , we get I2= 5.22 Kg.m^2

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---