In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and
ID: 2144599 • Letter: I
Question
In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and the circuit has R1 = 3.45 k? and L = 34 mH. PLEASE answer all and I will award full points
1)
f=
VrmsL=
At this frequency, what is the rms potential drop across the resistor?
VrmsR=
4)
VrmsTotal=
In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and the circuit has R1 = 3.45 k? and L = 34 mH. PLEASE answer all and I will award full points At what frequency will the rms current be 29.88 mA (milliamperes)? f= At this frequency, what is the rms potential drop across the inductor? VrmsL= At this frequency, what is the rms potential drop across the resistor? VrmsR= At this frequency, what is the rms potential drop across both the resistor and the inductor combined? VrmsTotal=Explanation / Answer
1)
Irms =Vrms/Z
Z =Vrms/Irms =110/(29.88*10*-3)
Z=3681.4 ohms
since Z=sqrt[R^2+XL^2]
3681.4 =sqrt[3450^2+XL^2]
XL =1284.6 ohms
since
XL=2pifL
=>f =XL/2piL =1284.6/2pi*34*10^-3
f=6013.25 Hz or 6.013 KHz
2)
VL =IXL =29.88*10^-3*1284.6
VL =38.38 V
3)
Vr =IR=29.88*10^-3*3450
Vr=103.09 V
4)
V=sqrt[Vr^2+VL^2]
V=110 V