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In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and

ID: 2144599 • Letter: I

Question

In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and the circuit has R1 = 3.45 k? and L = 34 mH. PLEASE answer all and I will award full points

1)

f=


VrmsL=

At this frequency, what is the rms potential drop across the resistor?

VrmsR=

4)

VrmsTotal=

In the circuit shown, the AC voltage source supplies an rms voltage of 110 V and the circuit has R1 = 3.45 k? and L = 34 mH. PLEASE answer all and I will award full points At what frequency will the rms current be 29.88 mA (milliamperes)? f= At this frequency, what is the rms potential drop across the inductor? VrmsL= At this frequency, what is the rms potential drop across the resistor? VrmsR= At this frequency, what is the rms potential drop across both the resistor and the inductor combined? VrmsTotal=

Explanation / Answer

1)

Irms =Vrms/Z

Z =Vrms/Irms =110/(29.88*10*-3)

Z=3681.4 ohms

since Z=sqrt[R^2+XL^2]

3681.4 =sqrt[3450^2+XL^2]

XL =1284.6 ohms

since

XL=2pifL

=>f =XL/2piL =1284.6/2pi*34*10^-3

f=6013.25 Hz or 6.013 KHz

2)

VL =IXL =29.88*10^-3*1284.6

VL =38.38 V

3)

Vr =IR=29.88*10^-3*3450

Vr=103.09 V

4)

V=sqrt[Vr^2+VL^2]

V=110 V