Pleasseee helpp and explain! The person shown is holding his arm out horizontall

Question

Pleasseee helpp and explain! The person shown is holding his arm out horizontally with a 3.50 weight in his hand. This weight is 60.0 from the shoulder joint. His forearm (including his hand) has a mass of 2.38 and is 34.0long; its center of mass is 43.0 from the shoulder joint, measured along the arm. His upper arm is 26.0 long and has a mass of 2.71 ; its center of mass is 13.0 from the shoulder joint. The deltoid muscle is attached to the humerus 15.0 from the shoulder joint and makes a 14.0 angle with the humerus.

Part A
What is the tension in the deltoid muscle?

Explanation / Answer

The torque = force * distance to pivot point Weight: M1 = 3.5*9.8*0.6 Forearm: M2 = 2.38*9.8*0.43 Upper arm: M3 = 2.71*9.8*0.13 Muscle: M4 = F * 0.15 *sin(14 degree) Equilibrium: M4 = M1 + M2 + M3 => F= 229.232 N

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