A)Calculate the location of the image of this seed. B) Calculate the height of t
ID: 2157891 • Letter: A
Question
A)Calculate the location of the image of this seed.
B)Calculate the height of the image of this seed.
C)Suppose now that the shell is reversed. Find the location of the seed's image.
D)Find the height of the seed's image
Explanation / Answer
A. given , height of seed = Hs = 3.30mm object distance = 15 cm. = u radius of curvature = 10.5cm . R= 2F ===> f= R/2 = 5.25 cm. by mirror formula , 1/f = 1/u + 1/v since the mirror is concave, the focal length is taken positive. substuting and finding out, v= 8.076 cm B. magnification = v/u = 8.076 / 15 = 0.538 so height of seed becomes, Hs X m = 3.3mm X 0.538 = 1.77 mm C . shell is reversed, then the glass piece becomes a convex mirror of the same focal length so, now since it is a convex mirror, the focal length is taken - ve . so computing tthe value of v, v= 3.88 cm. D. magnification .= v/u = 3.88/ 15 = 0.2592 height of seed = Hs X m = 3.3 X 0.2592 = 0.854 mm.