I have two plates separated by a distance d, with area A, charge |Q| (one plate

Question

I have two plates separated by a distance d, with area A, charge |Q| (one plate positive and the other negative), and a fixed potential difference between the plates |V|. We know that the area is much larger than the separation of the plates (A>>d) so we will talk about the electric field between the plates as if it were a uniform field, |E|. (For each part, enter the number or fraction the |E| field changes by. i.e. no change is 1, twice as much 2...)
a)If you double the distance between each plate instead, what happens to the electric field?
b)If you double the area of each plate instead, what happens to the electric field?
c)If you double the distance and the charge, what happends to the electric field?
Please give a brief explanation for each thank you.

Explanation / Answer

E0=V/d=C/qd=A0/qd^2

a)if d is doubled then E=E0/4 decreases by a factor 4

b)if area is doubled then E=2E= increases by a factor 2

c)if q and d are doubled then E= E0/4 decrease by a factor 4

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