a projectile is fired horizontally from a gun that is 45m above flat groun,emerg

Question

a projectile is fired horizontally from a gun that is 45m above flat groun,emerging from the gun with a soeed of 250m..my question is for the formula y-y sub0=(vsub0sinthetasub0)t-1/2gt^2....why is the sintheta 0 if the angle is not given..it says the initial vertical component of velocity of vsub0suby=0..is that the same of subtheta? Please explain to me throughly..Thank You

Explanation / Answer

the 3rd Quadrant (thats the bottom left one) the 1st Quadrant is the top right one and it goes anti-clockwise from there 1st Quadrant: - sin ? > 0 - cos ? > 0 - tan ? > 0 2nd Quadrant: - sin ? > 0 - cos ? < 0 - tan ? < 0 3rd Quadrant: - sin ? < 0 - cos ? < 0 - tan ? > 0 4th Quadrant: - sin ? < 0 - cos ? > 0 - tan ? < 0 u can remember it by labelling each quadrant a letter and writing a sentence for it e.g. ASTC= All Stations To Central A= all angles > 0 S= only sin ? > 0 T= only tan ? > 0 C= only cos ? > 0

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