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In the circuit shown in the figure 1 , current flows through the 5.00 ohm resist

ID: 2172307 • Letter: I

Question

In the circuit shown in the figure 1, current flows through the 5.00 ohmresistor in the direction shown, and this resistor is measured to be consuming energy at a rate of 20.8 W. The batteries have negligibly small internal resistance.


What current does the ammeter A read? I = ? A


In the circuit shown in the figure 1, current flows through the 5.00 ohmresistor in the direction shown, and this resistor is measured to be consuming energy at a rate of 20.8 W. The batteries have negligibly small internal resistance. What current does the ammeter A read? I = ? A

Explanation / Answer

power dissipiated by 5 ohm=i2r=20.8

i=20.8/5 =2.04

V across 5 ohm=2.04*5=10.2

applying loop law

15-10.2-7i=0

i=4.8/7 =0.685 which ammeter shows

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