A thin, cylindrical copper shell of diameter ds = 8 cm has along its axis a thin

Question

A thin, cylindrical copper shell of diameter ds = 8 cm has along its axis a thin metal wire of diameter dw = 6.15 ? 10-3 cm. (as shown in the diagram above.) The wire and the shell carry equal and opposite charges of 6.00 ? 10-9Ccm , distributed uniformly.

a)What is the magnitude of the electric field at a point r = 1.30 mm, where r is measured radially from the center of the inner wire?

b)What is the magnitude of the electric field at the surface of the wire?

I found a but cant for the life of my find b. I know you use the same formula and substitute for R with dw/2 but it is not working at all. Please help me find where I am going wrong!!

Explanation / Answer

Suppose charge on shell is q and that on wire is -q Linear charge density on wire lamda1 =-q/l [ where l is length of wire] Linear charge density on shell =q/l a)applying E=lamda*r/(2*pi*e0*R^2) [is the electric field for r

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---