Place the steps in the correct order: A. RNA polymerase disassociates from the D
ID: 218333 • Letter: P
Question
Place the steps in the correct order:
A. RNA polymerase disassociates from the DNA
B. TFIIH and TFIIE bind to the transcription initiation complex
C. the open complex becomes destabilized
D. TFIIB binds to the promoter and to TFIID
E. cleavage enzymes recognize the polyA sequence and cleave mRNA
F. rNTP's base pair with DNA
G. RNA polymerase II forms phososphodiester bonds between rNTPs
H. TFIID binds to the TATA box
I. RNA polymerase transcribes the poly-A sequence
J. TFIIH disrupts hydrogen bonds between the 2 strands of DNA
K. RNA polymerase II binds to the promoter with TFII-F
L. TFIIH attached phosphate groups to the C-terminal domain of RNA polymerase II
Explanation / Answer
These are the steps in the transcription process in Eukaryotic cells, where from a eukaryotic DNA, messanger RNA or mRNA will be formed and will be further translated into protein.
The correct order of sequence are:
I. K. RNA polymerase II binds to the promoter with TFII-F
II. H. TFIID binds to the TATA box
III. D. TFIIB binds to the promoter and to TFIID
IV. B. TFIIH and TFIIE bind to the transcription initiation complex
V. J. TFIIH disrupts hydrogen bonds between the 2 strands of DNA
VI. L. TFIIH attached phosphate groups to the C-terminal domain of RNA polymerase II
VII. F. rNTP's base pair with DNA
VIII. G. RNA polymerase II forms phososphodiester bonds between rNTPs
IX. C. the open complex becomes destabilized
X. A. RNA polymerase disassociates from the DNA
XI. E. cleavage enzymes recognize the polyA sequence and cleave mRNA
XII. I. RNA polymerase transcribes the poly-A sequence
The process of transcription is a bit complex than that in prokaryotes. There are various transcription factors acting simultaneously on the DNA template and RNA polymerase. Also Ploy A tal is transcribed at last and marks the end of transcription process and initiation of RNA processing step.